(M.DeV1) #1

Have no clue if I’m popular enough to have one of these yet but anyway, ask me questions.

#2

If 20 students are sitting in a circle, what is the probability student “x” is sitting next to student “y”?

#3

(M.DeV1) #4

Those are both variables silly.

#5

Well student x is sitting next to two people at any given time. On one side, there’s a 1/19 chance of it being student y, on his other side, there’s a 1/18 chance. So there’s about an 11% chance student x would be sitting next to student y.

You’re not off to a good start, Mason

#6

19*18=342

1/342=0.002

So, wouldn’t it be a 0.002% chance? I just know I did something wrong there, though…

(NotATyrant) #7

Ask me questions too! I haven’t gotten any yet… :’(

#8

#9

Student Y can only be on one side at a time, so its an OR problem, rather than and AND problem. With OR problems you add the probability of either A or B occurring, with an AND problem you multiply the probability of A and B occurring.

Therefore, it would be
(1/18) + (1/19) = .108

Man, looks like AP stats paid off.

(M.DeV1) #10

I leave for a few hours and come back to this…

#11

How much wood would a woodchuck chuck if a woodchuck could chuck wood.

#12

A woodchuck would chuck as much wood as a woodchuck could chuck if a woodchuck could chuck wood.