Have no clue if I’m popular enough to have one of these yet but anyway, ask me questions.
If 20 students are sitting in a circle, what is the probability student “x” is sitting next to student “y”?
Those are both variables silly.
Well student x is sitting next to two people at any given time. On one side, there’s a 1/19 chance of it being student y, on his other side, there’s a 1/18 chance. So there’s about an 11% chance student x would be sitting next to student y.
You’re not off to a good start, Mason 
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19*18=342
1/342=0.002
So, wouldn’t it be a 0.002% chance? I just know I did something wrong there, though…
Ask me questions too! I haven’t gotten any yet… :’(
Student Y can only be on one side at a time, so its an OR problem, rather than and AND problem. With OR problems you add the probability of either A or B occurring, with an AND problem you multiply the probability of A and B occurring.
Therefore, it would be
(1/18) + (1/19) = .108
Man, looks like AP stats paid off.
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I leave for a few hours and come back to this…
How much wood would a woodchuck chuck if a woodchuck could chuck wood. 
A woodchuck would chuck as much wood as a woodchuck could chuck if a woodchuck could chuck wood.